Question

The value of $\frac{pV}{T}$ for one mole of an ideal gas is nearly equal to

• A. $2Jmo{l}^{-1}{K}^{-1}$
• B. $8.3Jmo{l}^{-1}{K}^{-1}$
• C. $4.2mo{l}^{-1}{K}^{-1}$
• D. $2calmo{l}^{-1}{K}^{-1}$

Answer 1

The correct option is D $2calmo{l}^{-1}{K}^{-1}$

$\frac{PV}{T}=nR$

for $n=1$

$\begin{array}{c}\frac{PV}{T}=R\\ =8.3Jmo{l}^{-1}{k}^{-1}\end{array}$

Then,

Option $B$ is correct answer.