The value of $^{10} C_{4} +^{10} C_{5}$ is:

462

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466

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469

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465

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Solution

The correct option is A 462
$^{10} C_{4} +^{10} C_{5} =^{11} C_{5}$
$(^{n} C_{r} +^{n} C_{r - 1} =^{n + 1} C_{r})$
$= 462$

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Similar questions

C_{1} = C_{2} = C_{3} = C_{4} = 8

μ

; C_{5} = 10 μ C

C_{1} = C_{2} = C_{3} = C_{4} = 10 μ F

C_{5} = C_{6} = C_{7} = C_{8} = 5 μ F

(^{21} C_{1} -^{10} C_{1}) + (^{21} C_{2} -^{10} C_{2}) + (^{21} C_{3} -^{10} C_{3}) + (^{21} C_{4} -^{10} C_{4}) + . . . + (^{21} C_{10} -^{10} C_{10})

^{n} C_{4},^{n} C_{5}

^{n} C_{6}

The order of the differential equation whose general
solution is

$y = C_{1} e^{x} + C_{2} e^{2 x} + C_{3} e^{3 x} + C_{4} e^{x + C_{5}}$ where $C_{1}, C_{2}, C_{3}, C_{4}, C_{5}$ are arbitrary
constant is-

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