The value of 2√2cos45∘cos60∘+2√3sin30∘tan60∘−cos0∘ is
Show that:
(i) 1−sin 60∘cos 60∘=tan 60∘−1tan 60∘+1
(ii) cos 30∘+sin 60∘1+sin 30∘+cos 60∘=cos 30∘