Question

The value of $4{\cos }^2{60}^{\circ }+4{\tan }^2{45}^{\circ }-cose{c}^2{30}^{\circ }$ is

• A. 0
• B. 2
• C. 1
• D. $\frac{1}{2}$

Answer 1

The correct option is C 1

$\theta$	$0^{\circ }$	${30}^{\circ }$	${45}^{\circ }$	${60}^{\circ }$	${90}^{\circ }$
$\sin \theta$	$0$	$\frac{1}{2}$	$\frac{1}{\sqrt{2}}$	$\frac{\sqrt{3}}{2}$	$1$
$\cos \theta$	$1$	$\frac{\sqrt{3}}{2}$	$\frac{1}{\sqrt{2}}$	$\frac{1}{2}$	$0$
$\tan \theta$	$0$	$\frac{1}{\sqrt{3}}$	$1$	$\sqrt{3}$	Not defined
$\cot \theta$	Not defined	$\sqrt{3}$	$1$	$\frac{1}{\sqrt{3}}$	$0$
$\sec \theta$	$1$	$\frac{2}{\sqrt{3}}$	$\sqrt{2}$	$2$	Not defined
$Cosec\theta$	Not defined	$2$	$\sqrt{2}$	$\frac{2}{\sqrt{3}}$	$1$

$4.\frac{1}{4}+4.1-4=1$