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B
2
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C
4
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D
8
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Solution
The correct option is C 4 a=csc10−√3sec10 ⇒a=cos10−√3sin10sin10cos10=4(sin30cos10−cos30sin10)2sin10cos10 ⇒a=4sin20sin20=4{∵2sinAcosA=sin2A&sinAcosB−cosAsinB=sin(A−B)} Ans: C