The value of $cos 1^{0} cos 2^{0} cos 3^{0} . . . . cos 179^{0}$ is

\frac{1}{\sqrt{2}}

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Solution

The correct option is D $0$
We can solve $cos 1^{0} cos 2^{0} cos 3^{0} . . . cos 179^{0}$ as
$= cos 1^{0} cos 2^{0} cos 3^{0} . . .$
$= cos 90^{0} . . . cos 179^{0}$
$= 0$ .....[Since $cos 90^{0} = 0$ ]

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cos $1^{o}$ cos $2^{o}$ cos $3^{o}$ ..... cos $180^{o}$ = ?

(a) -1 (b) 1 (c) 0 (d) $\frac{1}{2}$

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