CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of cos250+cos2100+cos2150+cos2200+cos2700+cos2750+cos2800+cos2850 is equal to

Open in App
Solution

The value of cos250+cos2100+cos2150+cos2200+cos2700+cos2750+cos2800+cos2850
=(cos250+sin250)+(cos2100+sin2100)+(cos2150+sin2150)+(cos2200+sin2200)
=1+1+1+1=4
[cos850=cos(90050)=sin50etc]

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Trigonometric Identities_Concept
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon