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Question

The value of cosπ7+cos2π7+cos3π7+cos4π7+cos5π7+cos6π7+cos7π7is

A
1
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B
1
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C
0
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D
none of these
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Solution

The correct option is C 1

Using identity cosA+cosB=2cos(A+B2)cos(AB2)

a=cosπ7+cos2π7+cos3π7+cos4π7+cos5π7+cos6π7+cos7π7

a=(cosπ7+cos6π7)+(cos2π7+cos5π7)+(cos3π7+cos4π7)+cosπ

a=2cos[12(π7+6π7)]cos[12(π76π7)]+2cos[12(2π7+5π7)]cos[12(2π75π7)]+2cos[12(3π7+4π7)]cos[12(3π74π7)]1

a=2cosπ2[cos5π14+cos3π14+cosπ14]1

a=1

Ans-Option B.


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