Question

The value of $\frac{(0.6{)}^0-(0.1{)}^1}{\left(3/2^3{)}^{-1}\right(3/2{)}^3+(-1/3{)}^{-1}}$ is

• A. $\frac{3}{20}$
• B. $-\frac{3}{20}$
• C. $\frac{20}{3}$
• D. $-\frac{1}{20}$

Answer 1

The correct option is A $\frac{3}{20}$

$\frac{(0.6{)}^{\circ }-(0.1{)}^1}{\left(3/2^3{)}^{-1}\right(3/2{)}^3+(-1/3{)}^{-1}}$
$\Rightarrow \frac{1-.1}{\left(\frac{2^3}{3}\right){\left(\frac{3}{2}\right)}^3+{(-\frac{1}{3})}^{-1}}$
$\Rightarrow \frac{.9}{\frac{8}{3}\times \frac{27}{8}-3}$
$\Rightarrow \frac{.9}{9-3}$
$\Rightarrow \frac{.9}{6}$
$\Rightarrow \frac{9}{60}\Rightarrow \frac{3}{20}$