Question

The value of $\frac{(0.6{)}^0-(0.1{)}^1}{{\left(\frac{3}{2^3}\right)}^{-1}{\left(\frac{3}{2}\right)}^3+{\left(\frac{-1}{3}\right)}^{-1}}$ is

• A. $\frac{3}{2}$
• B. $-\frac{3}{2}$
• C. $\frac{2}{3}$
• D. $-\frac{1}{2}$

Answer 1

Answer: (B)

$-\frac{3}{2}$

$\frac{(0.6{)}^0-(0.1{)}^1}{{\left(\frac{3}{2^3}\right)}^{-1}{\left(\frac{3}{2}\right)}^3+{\left(\frac{-1}{3}\right)}^{-1}}$
$=\frac{1-\frac{1}{0.1}}{\left(\frac{2^3}{3}\right)\cdot {\left(\frac{3}{2}\right)}^3+(-3)}$
$=\frac{1-10}{\frac{8}{3}\cdot \frac{27}{8}-3}=-\frac{9}{6}=-\frac{3}{2}$