Question

The value of $\frac{{\left(0.6\right)}^0-{\left(0.1\right)}^{-1}}{{\left(\frac{3}{2^3}\right)}^{-1}{\left(\frac{3}{2}\right)}^3+{(-\frac{1}{3})}^{-1}}$ is

• A. $\frac{3}{2}$
• B. $-\frac{3}{2}$
• C. $\frac{2}{3}$
• D. $-\frac{1}{2}$

Answer 1

The correct option is B $-\frac{3}{2}$

$\frac{{\left(0.6\right)}^0-{\left(0.1\right)}^{-1}}{(\frac{3}{2^3}{)}^{-1}{\left(\frac{3}{2}\right)}^3+{\left(\frac{-1}{3}\right)}^{-1}}=\frac{1-10}{\frac{8}{3}.\frac{27}{8}-3}=\frac{-9}{9-3}=\frac{-9}{6}=\frac{-3}{2}$