Question

The value of $\frac{2\sin {67}^{\circ }}{\cos {23}^{\circ }}-\frac{\cot {40}^{\circ }}{\tan {50}^{\circ }}$

• A. 0
• B. 1
• C. -1
• D. None

Answer 1

Answer: (B)

1

$\frac{2\sin {67}^0}{\cos {23}^0}-\frac{\cot {40}^0}{\tan {50}^0}=\frac{2\sin ({90}^0-{23}^0)}{\cos {23}^0}-\frac{\cot ({90}^0-{50}^0)}{\tan {50}^0}$

$=\frac{2\cos {23}^0}{\cos {23}^0}-\frac{\tan {50}^0}{\tan {50}^0}$

$=2-1=1$

Option B is correct.