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Byju's Answer
Standard XII
Mathematics
Definite Integral as Limit of Sum
The value of ...
Question
The value of
cot
50
o
tan
40
o
is :
A
0
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B
1
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C
2
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D
3
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Solution
The correct option is
B
1
The value of
cot
50
o
tan
40
o
=
cot
(
90
o
−
40
o
)
tan
40
o
=
tan
40
o
tan
40
o
=
1
[
∵
cot
(
90
o
−
θ
)
=
tan
θ
]
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0
Similar questions
Q.
The value of
2
cos
67
o
sin
23
o
−
tan
40
o
cot
50
o
is :
Q.
The value of
tan
40
o
+
2
tan
10
o
is equal to
Q.
The value of
cos
(
40
o
+
θ
)
−
sin
(
50
o
−
θ
)
+
cos
2
40
o
+
cos
2
50
o
sin
2
40
o
+
sin
2
50
o
is :
Q.
tan
40
o
+
tan
60
o
+
tan
80
o
=
tan
40
o
⋅
tan
60
o
⋅
tan
80
o
Q.
Solve:
tan
20
o
+
tan
40
o
+
t
a
n
60
o
+
.
.
.
tan
180
o
=
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