Question

The value of $\frac{\sin {19}^{\circ }}{\cos {71}^{\circ }}+\frac{\cos {73}^{\circ }}{\sin {17}^{\circ }}$ is equal to:

• A. $0$
• B. $1$
• C. $2$
• D. $\frac{1}{2}$

Answer 1

The correct option is C $2$

Given exp.$=\frac{\sin ({90}^{\circ }-{71}^{\circ })}{\cos {71}^{\circ }}+\frac{\cos {73}^{\circ }}{\sin ({90}^{\circ }-{73}^{\circ })}$

$=\frac{\cos {71}^{\circ }}{\cos {71}^{\circ }}+\frac{\cos {73}^{\circ }}{\cos {73}^{\circ }}$ .......... $(\because \sin ({90}^{\circ }-\theta )=\cos \theta )$

$=1+1=2$