The value of sin 60 o -cos 2 45 o - 30 o -5cos 90 o is -

The correct option is A 0 sin 60 ^ o #160;/cos^ 2 45 ^ o 30 ^ o +5cos 90 ^ o #160; #160; =√( 3 ) #160;/ 2 #160;/ 1 / 2 #160; ...

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Integration by Substitution

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Question

The value of $\frac{sin 60^{o}}{{cos}^{2} 45^{o}} - cot 30^{o} + 5 cos 90^{o}$ is :

0

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1

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2

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\frac{1}{2}

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\frac{1 + {tan}^{2} 30^{o}}{1 - {tan}^{2} 30^{o}} + {csc}^{2} 60^{0} - {cos}^{2} 45^{o} + {sin}^{2} 45^{o} + \frac{1 + {cot}^{2} 60^{o}}{1 - {cot}^{2} 60^{o}}

({sin}^{2} 30^{o} + {cos}^{2} 30^{o}) - ({sin}^{2} 60^{o} + {cos}^{2} 60^{o}) + ({sin}^{2} 45^{o} + {cos}^{2} 45^{o})

{sin}^{2} 30^{o} {cos}^{2} 45^{o} + 4 {tan}^{2} 30^{o} + \frac{1}{2} {sin}^{2} 90^{o} - 2 {cos}^{2} 90^{o}

{cos}^{2} 75^{o} + {cos}^{2} 45^{o} + {cos}^{2} 15^{o} - {cos}^{2} 30^{o} - {cos}^{2} 60^{o}

\frac{{tan}^{2} 60^{o} - 2 {tan}^{2} 45^{o} + {sec}^{2} 30^{o}}{3 {sin}^{2} 45^{o} sin 90^{o} + {cos}^{2} 60^{o} {cos}^{3} 0^{o}}

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