Question

The value of $\frac{\tan {49}^o}{\cot {41}^o}$ is :

• A. $1$
• B. $2$
• C. $0$
• D. $3$

Answer 1

The correct option is A $1$

The value of $\frac{\tan {49}^o}{\cot {41}^o}$

$=\frac{\tan ({90}^o-{41}^o)}{\cot {41}^o}$

$=\frac{\cot {41}^o}{\cot {41}^o}=1$
$[\because \tan ({90}^o-\theta )=\cot \theta ]$