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B
x
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C
y
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D
0
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Solution
The correct option is D 0 x+yx−y+x−yx+y−2(x2+y2)x2−y2 ⇒(x+y)(x+y)+(x−y)(x−y)−2(x2+y2)x2−y2 ⇒x2+y2+2xy+x2+y2−2xy−2(x2+y2)x2−y2 ⇒x2+y2+2xy+x2+y2−2xy−2x2−2y2x2−y2 ⇒0x2−y2=0