Question

The value of $G=6.67\times {10}^{-10}N{m}^2(kg{)}^{-2}$ its numerical value in CGS system will be

• A. $6.67\times {10}^{-7}$
• B. $6.67\times {10}^{-6}$
• C. 6.67
• D. $6.67\times {10}^{-5}$

Answer 1

The correct option is A $6.67\times {10}^{-7}$

The value of G is given in SI unit.

We know that, $1N={10}^5$ dyne, $1m=100cm={10}^{2}cm$ and $1kg=1000gm={10}^{3}gm$

Now putting these values in $G$, we get $G=(6.67\times {10}^{-10})\left({10}^{5}dyne\right)\left({10}^{2}cm{)}^2\right({10}^{3}gm{)}^{-2}$

$\Rightarrow G=6.67\times {10}^{-10}\times {10}^5\times {10}^4\times {10}^{-6}dyne$ $c{m}^2(gm{)}^{-2}=6.67\times {10}^{-7}dyne$ $c{m}^2(gm{)}^{-2}$