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B
2→r
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C
3→r
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D
4→r
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Solution
The correct option is B2→r Let →r=x^i+y^j+z^k Then ^i×(→r×^i)+^j×(→r×^j)+^k×(→r×^k)=(^i.^i)→r−(^i.→r)^i+(^j.^j)→r−(^j→r)^j+(^k.^k)→r−(^k→r)^k=3→r−^i(^i.(x^i+y^j+z^k))−^j(^j.(x^i+y^j+z^k))−^k(^k.(x^i+y^j+z^k))=3→r−(x^i+y^j+z^k)=3→r−→r=2→r