wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of π0|cosx|dx is

A
2π
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2/π
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
π
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2
π0|cosx|dx
=π/20cosxdx0π/2cosxdx
=[sinx]π/20[sinx]π/2
=sinπ2sin0sinπ+sinπ2
=1+1
2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon