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Question

The value of bax|x|dx,a<b<0 is

A
(|a|+|b|)
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B
|b||a|
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C
|a||b|
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D
|a|+|b|
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Solution

The correct option is B |b||a|
x|x|dx

=|x|+C

bax|x|dx

=[|x|]ba

=|b||a|

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