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Question

The value of cosx+xsinxx2+xcosxdx is

A
logsinx1+cosx+C
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B
logsinxx+cosx+C
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C
log2sinxx+cosx+C
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D
logxx+cosx+C
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Solution

The correct option is D logxx+cosx+C
cosx+xsinxx2+xcosxdx
=x+cosxx+xsinxx2+xcosxdx
=dxxx(1sinx)x(x+cosx)dx
=logxlog(x+cosx)+C
=logxx+cosx+C

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