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Question

The value of 1x7x(1+x7)dx is equal to

A
ln|x|+27ln1+x7+C
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B
ln|x|27ln1x7+C
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C
ln|x|27ln1+x7+C
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D
ln|x|+27ln1x7+C
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Solution

The correct option is C ln|x|27ln1+x7+C
1x7x(1+x7)=(1+x7)2x7x(1+x7)=1x2x61+x7

1x7x(1+x7)dx=1xdx2x61+x7dx

=1xdx277x61+x7dx

=lnx27ln1+x7+C ........ f(x)f(x)dx=log(f(x))+c

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