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Question

The value of π20cos2x dx is

A
π3
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B
π4
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C
0
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D
π
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Solution

The correct option is B π4
Let I=π20cos2x dx
we know that,
cos2x=2cos2x1
cos2x=1+cos2x2
I=π/20(1+cos2x2)dx=12π20dx+12π20cos2x dx
=12[x]π20+12[sin2x2]π20=12(π20)+14(00)=π4

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