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Byju's Answer
Standard XII
Mathematics
Second Fundamental Theorem of Calculus
The value of ...
Question
The value of
π
∫
0
cos
101
x
d
x
is equal to
A
π
4
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B
1
102
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C
(
π
3
)
101
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D
0
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Solution
The correct option is
D
0
Let
I
=
π
∫
0
cos
101
x
d
x
⋯
(
i
)
⇒
I
=
π
∫
0
[
cos
(
π
−
x
)
]
101
d
x
⇒
I
=
π
∫
0
−
cos
101
x
d
x
⋯
(
i
i
)
Adding
(
i
)
and
(
i
i
)
, we get
2
I
=
0
∴
I
=
0
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0
Similar questions
Q.
If
a
1
,
a
2
and
a
3
are the three values of
a
which satisfy the equation
π
/
2
∫
0
(
sin
x
+
a
cos
x
)
3
d
x
−
4
a
π
−
2
π
/
2
∫
0
x
cos
x
d
x
=
2
,
then the value of
1000
(
a
2
1
+
a
2
2
+
a
2
3
)
is
Q.
Consider
I
1
=
π
/
4
∫
0
e
x
2
d
x
,
I
2
=
π
/
4
∫
0
e
x
d
x
,
I
3
=
π
/
4
∫
0
e
x
2
cos
x
d
x
,
I
4
=
π
/
4
∫
0
e
x
2
sin
x
d
x
Statement
1
:
I
2
>
I
1
>
I
3
>
I
4
Statement
2
:
For
x
∈
(
0
,
π
4
)
,
x
>
x
2
and
cos
x
>
sin
x
Q.
The value of
∫
π
0
sin
120
x
cos
101
x
d
x
equals
Q.
The value of
∫
π
−
π
sin
3
x
cos
2
x
dx
is equal to