Question

The value of $\underset{-1}{\overset{1}{\int }}|x|dx$

• A. $1$
• B. $0$
• C. $2$
• D. $-1$

Answer 1

Answer: (A)

$1$

$\underset{-1}{\overset{1}{\int }}|x|dx$

$=2\underset{0}{\overset{1}{\int }}xdx$ [ Since $|x|$ is an even function then using definite integral property]

$=2{\left[\frac{x^2}{2}\right]}_{x=0}^{x=1}$

$=2.\frac{1}{2}$

$=1$