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Question

The value of 83sinx+1x+1dx is

A
2cos22cos3
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B
1
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C
cos2cos3
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D
2cos2+2cos3
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Solution

The correct option is A 2cos22cos3
I=83sinx+1x+1dx
Put x+1=t1x+1dx=2dt
I=322sintdt=2cost32
=2(cos3cos2)
=2cos22cos3

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