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Question

The value of π/2π/2dxsin3x+sinxis

A
0
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B
2
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C
1
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D
none of these
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Solution

The correct option is A 0
Let I=π2π2dxsin3x+sinx
Using baf(x)dx=baf(a+bx)dx
I=π2π2dxsin3(x)+sin(x)dx
=π2π2dxsin3x+sinxdx=I2I=II=0

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