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Question

The value of π/2π/212(1cos2x) dx is

A
0
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B
2
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C
12
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D
None of these.
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Solution

The correct option is A 2
I=π/2π/212.2sin2xdx=π/2π/2|sinx|dx,
=2π/20|sinx|dx
=2π/20sinxdx, |sinx|=sinx on the interval (0,π/2)
=2(cosx)π/20=2
Ans: B

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