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Question

The value of tanx1/etdt1+t2+cotx1/edtt(1+t2) is

A
12+tan2x
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B
1
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C
π/4
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D
2π11dt1+t2
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Solution

The correct option is A 1
tanx1/et1+t2dt+cotx1/edtt(1+t2)
=tanx1/et1+t2dt+cotx1/e(1t11+t2)dt
=12[log(1+t2)]tanx1/e+[logt]cotx1/e[tan1t]cotx1/e=1

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