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Question

The value of xsinx(cosxlnx+1xsinx)dx is
(where C is constant of integration)

A
xsinx+C
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B
xsinx+C
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C
xsinx+C
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D
xsinx+C
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Solution

The correct option is A xsinx+C
Let I=xsinx(cosxlnx+1xsinx)dx
put xsinx=t
xsinxddx(sinxlnx)=dt
xsinx(cosxlnx+sinxx)dx=dt
Clearly I=ddx(xsinx)dx
I=xsinx+C

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