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Question
The value of Kc for the reaction 3O2(g)⇌2O3(g) is 2.0×10−50 at 25oC. If the equilibrium concentration of O2 in air at 25oC is 1.6×10−2 M, what is the concentration of O3?
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Solution
The equilibrium constant expression is
Kc=[O3]2[O2]3
2.0×10−50=[O3]2(1.6×10−2)3
[O3]2=2.0×10−50×(1.6×10−2)3=8.192×10−56
Hence, the equilibrium concentration of ozone is
[O3]=2.86×10−28M
Kc=[O3]2[O2]3
2.0×10−50=[O3]2(1.6×10−2)3
[O3]2=2.0×10−50×(1.6×10−2)3=8.192×10−56
Hence, the equilibrium concentration of ozone is
[O3]=2.86×10−28M
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