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B
1
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C
2
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D
3
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Solution
The correct option is A 0 (1+cosAsinA−1sinA)(1+sinAcosA+1cosA) =(sinA+cosA−1sinA)(cosA+sinA+1cosA) =(sinA+cosA)2−1sinA.cosA =sin2A+cos2A+2sinA.cosA−1sinA.cosA =sin2A+cos2A−1sinA.cosA=2sinA.cosAsinA.cosA=2