The value of - 11 12 13 12 13 14 13 14 15 -is

The correct option is B 0 | 11 amp; 12 amp; 13 12 amp; 13 amp; 14 13 amp; 14 amp; 15 | R _ 2 → R _ 2 R _ 1 , R _ 3 → R ...

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Theorems for Continuity

The value of ...

Question

The value of $∣ ∣ ∣ ∣ \begin{matrix} 11 & 12 & 13 12 & 13 & 14 13 & 14 & 15 \end{matrix} ∣ ∣ ∣ ∣$ ,is

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-1

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x + y = 17

x^{2} + y^{2} = 167

x y

K_{c}

C a C O_{3 (s)} ⇌ C a O_{(} s) + C O_{2 (g)}

K_{p} = 167

1073

(3 + \frac{5}{- 7}) = ?

\frac{- 16}{7}

\frac{16}{7}

\frac{- 26}{7}

\frac{- 8}{7}

(\frac{- 3}{17}) + (\frac{- 12}{5}) = (\frac{- 12}{5}) + (. . . . . .)

- 9 + \frac{- 21}{8} = (. . . . . .) + (- 9)

(\frac{- 8}{13} + \frac{3}{7}) + (\frac{- 13}{4}) = (. . . . . .) + [\frac{3}{7} + (\frac{- 13}{4})]

- 12 + (\frac{7}{12} + \frac{- 9}{11}) = (- 12 + \frac{7}{12}) + (. . . . . .)

\frac{19}{- 5} + (\frac{- 3}{11} + \frac{- 7}{8}) = \{\frac{19}{- 5} + (. . . . . .)\} + \frac{- 7}{8}

\frac{- 16}{7} + . . . . . . = . . . . . . + \frac{- 16}{7} = \frac{- 16}{7}

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