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Question

The value of ∣∣ ∣∣b+caabc+abcca+b∣∣ ∣∣, is

A
6abc
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B
a+b+c
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C
4abc
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D
abc
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Solution

The correct option is C 4abc
∣ ∣b+caabc+abcca+b∣ ∣
R1R1+R2+R3
∣ ∣2(b+c)2(a+c)2(a+b)bc+abcca+b∣ ∣
=2∣ ∣b+ca+ca+bbc+abcca+b∣ ∣
R1R1R3
=2∣ ∣ba0bc+abcca+b∣ ∣
R2R2R1
=2∣ ∣ba00cbcca+b∣ ∣
On expanding the above determinant we get,
=2(abc+abc)=4abc
Hence, option 'C' is correct.

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