Question

The value of $[{\left(0.98\right)}^3+{\left(0.02\right)}^3+3\times 0.98\times 0.02-1]$ is

• A. 0
• B. 1
• C. 1.09
• D. 1.98

Answer 1

The correct option is A 0

$a^3+b^3+3ab(a+b)=(a+b{)}^3$

$Herea=0.98,b=0.2$

So, $\left[\right(0.98{)}^3+(0.02{)}^3+3\times 0.98\times 0.02-1]=\left[\right(0.98+0.02{)}^3-1]={1.00}^3-1=0$