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Question

The value of {|a×b|2+(ab)2}÷(a2b2) is

A
unity
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B
zero
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C
2
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D
None of these
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Solution

The correct option is D unity
{|a×b|2+(ab)2}÷(a2b2)
=(|a||b|sinθ)2+(|a||b|cosθ)2a2b2
=a2b2(sin2θ+cos2θ)a2b2=1

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