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Question

The value of (xb+cca)1ab(xc+aab)1bc(xa+bbc)1ca is

A
1
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B
a
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C
b
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D
c
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Solution

The correct option is D 1
(xb+cca)1ab×(xc+aab)1bc×(xa+bbc)1ca

xb+c(ca)(ab)×xc+a(ab)(bc)×xa+b(bc)(ca)

xb+c(ca)(ab)+c+a(ab)(bc)+a+b(bc)(ca)

xb2c2+c2a2+a2b2(ab)(bc)(ca)

x0(ab)(bc)(ca)
x0
1

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