The value of (xb+cc−a)1a−b(xc+aa−b)1b−c(xa+bb−c)1c−a is
Question:- (1/x a-b)1/(a-c) . (1/x b-c)1/(b-a) . (1/x c-a) 1/(c-b) = ?
A) 0
B) 1
C) (a+b+c)
D) (a-b+c) 2