The value of limh - 0x-h1n-x1nh is

lim_h→ 0(x+h)^1/n x^1/nh Apply L Hospital's rule =lim_h→ 01/n(x+h)^1 n/n1 =1n(x)^1 nn ...

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Existence of Limit

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The value of $lim h \to 0 \frac{(x + h)^{\frac{1}{n}} - x^{\frac{1}{n}}}{h}$ is

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