wiz-icon
MyQuestionIcon
MyQuestionIcon
5
You visited us 5 times! Enjoying our articles? Unlock Full Access!
Question

The value of limx(p1/x+q1/x+r1/x+s1/x4)3x, where p,q,r,s>0 is equal to

A
pqrs
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(pqrs)3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(pqrs)3/2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(pqrs)3/4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D (pqrs)3/4
L=limx(p1/x+q1/x+r1/x+s1/x4)3x, where p,q,r,s>0
Put 1x=z
As x,z0
L=limz0(pz+qz+rz+sz4)3/z
which is in the form of 1.

L=elimz0(pz+qz+rz+sz41)×3z
=elimz0(pz1z+qz1z+rz1z+sz1z)×34
=e3/4(logep+logeq+loger+loges)
=e3/4loge(pqrs)
=(pqrs)3/4

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Standard Expansions and Standard Limits
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon