Question

The value of $\underset{n\to \infty }{lim}\frac{3^n+2^n}{3^n-2^n}$ is

• A. $-1$
• B. $1$
• C. $0$
• D. $\infty$

Answer 1

The correct option is B $1$

Let, $L=\underset{x\to \infty }{lim}\frac{3^n+2^n}{3^n-2^n}$
Divide numerator and denominator by $3^n$
$\therefore L=\underset{x\to \infty }{lim}\frac{1+(2/3{)}^n}{1-(2/3{)}^n}=\frac{1+0}{1-0}=1$