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Question

The value of limn[nn2+12+nn2+22++nn2+n2] is

A
π4
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Solution

The correct option is A π4
limn[nn2+12+nn2+22++nn2+n2]
=limnnr=1nn2+r2=limn1nnr=111+(rn)2
=10dx1+x2=[tan1x]10
=π4

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