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Question

The value of limx01/2(1cos2x)x is equal to.

A
0
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B
1
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C
1
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D
None of these
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Solution

The correct option is C None of these
limx012(1=cos2x)x
limx012(1(1cos2x))x
=limx0|sinx|x
L.H.L
=limx0sinxx=1
R.H.L
=limx0+sinxx=+1
L.H.LR.H.L
So Limit does not exist
(D) option

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