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Byju's Answer
Standard XII
Mathematics
Right Hand Limit
The value of ...
Question
The value of
lim
x
→
1
100
1
−
x
100
−
50
1
−
x
50
is
Open in App
Solution
L
=
lim
x
→
1
100
1
−
x
100
−
50
1
−
x
50
Putting
x
=
1
y
, we get
L
=
lim
y
→
1
100
y
100
y
100
−
1
−
50
y
50
y
50
−
1
⇒
L
=
lim
y
→
1
100
(
y
100
−
1
+
1
)
y
100
−
1
−
50
(
y
50
−
1
+
1
)
y
50
−
1
⇒
L
=
lim
y
→
1
[
100
−
50
−
(
100
1
−
y
100
−
50
1
−
y
50
)
]
⇒
L
=
50
−
L
∴
L
=
25
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3
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