Question

The value of $\underset{x\to 2}{lim}\frac{(x^4-16)}{x-2}$ is

• A. $33$
• B. $32$
• C. $30$
• D. $1$
• E. $0$

Answer 1

Answer: (B)

$32$

The value of the limit $\underset{x\to 2}{lim}\frac{x^4-16}{x-2}$ is

$=\underset{x\to 2}{lim}\frac{(x^2-4)(x^2+4)}{x-2}$

$=\underset{x\to 2}{lim}\frac{(x-2)(x+2)(x^2+4)}{x-2}$

$=\underset{x\to 2}{lim}(x+2)(x^2+4)$

$=32$