The value of limx - -2x2 - x - 62-x - 22 is-

The correct option is A 25 We have #160;lim_x → 2(x^2 x 6)^2/(x + 2)^2 = lim_x → 2(x 3)^2 (x + 2)^2/(x +2)^2 #160;= lim_x → 2 (x 3 ...

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Standard XII

Mathematics

Algebra of Limits

The value of ...

Question

The value of $lim x \to - 2 \frac{(x^{2} - x - 6)^{2}}{(x + 2)^{2}}$ is?

6

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25

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9

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16

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Solution

The correct option is A $25$
We have
$lim x \to - 2 \frac{(x^{2} - x - 6)^{2}}{(x + 2)^{2}}$
$= lim x \to - 2 \frac{(x - 3)^{2} (x + 2)^{2}}{(x + 2)^{2}}$
$= lim x \to - 2 (x - 3)^{2} = (- 2 - 3)^{2} = 25$
Hence, option 'B' is correct.

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The value of limx→−2(x2−x−6)2(x+2)2 is?

The correct option is A 25We have limx→−2(x2−x−6)2(x+2)2=limx→−2(x−3)2(x+2)2(x+2)2=limx→−2(x−3)2=(−2−3)2=25Hence, option 'B' is correct.

The value of $lim x \to - 2 \frac{(x^{2} - x - 6)^{2}}{(x + 2)^{2}}$ is?

The correct option is A $25$
We have
$lim x \to - 2 \frac{(x^{2} - x - 6)^{2}}{(x + 2)^{2}}$
$= lim x \to - 2 \frac{(x - 3)^{2} (x + 2)^{2}}{(x + 2)^{2}}$
$= lim x \to - 2 (x - 3)^{2} = (- 2 - 3)^{2} = 25$
Hence, option 'B' is correct.