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Question

The value of limx⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪xx+3xx+3xx+3x⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ is

A
0
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B
1
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C
2
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D
12
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Solution

The correct option is C 1
Let y=xx+3xx+3x
=xx+1x2/3xx+3x=xx+yx2/3
y=x5/3x5/3+y
y2+(x5/3)yx5/3=0
Thus y=x5/3±x10/3+4x5/32
=x5/3+x10/3+4x5/32 (y>0)
=4x5/32(x10/3+4x5/3+x5/3)=2(1+4x5/3)+1
Therefore, limxy=21+0+1 =22=1

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