Question

The value of $(\log 5+\log 8-2\log 2)$ is equal to

• A. $1$
• B. $2$
• C. $0$
• D. $-3$

Answer 1

The correct option is A $1$

$x=\log 5+\log 8-2\log 2$

$\therefore x=\log 5+\log 8-\log 2^2$ ....($\log a^b=b\log a$)

$\therefore x=\log 5+\log \frac{8}{4}$ ....($\log \frac{a}{b}=\log a-\log b$, $\log a.b=\log a+\log b$)

$\therefore x=\log 10=1$