The correct option is D −c4
Let P(x1,y1)=(ct,ct),(i=1,2,3,4) are points on the rectangular hyperbola xy=c2
and equation ofnonnal to the hyperbola xy=c2 at (x1,y1)
is xx1−yy1=x21−y21 so replacing
x1→ct and y1→ct
we get equation of normal given by
xct−yct=c2t2−c2t2
⇒xt3−yt−ct4+c=0 which passes through the points (a,b)
∴ct4−at3+bt−c=0 which is fourth degree equation in t, so in general 4 normals can be drawn as the fourth degree equation has four roots. Let t1,t2,t3,t4 be the roots of fourth degree equation, then
∑ti=ac∑t1t2=0,∑t1t2t3=−bc and t1t2t3t4=−1
∏xi=c4∏ti=c4(−1)=−c4
and ∏yi=c4(1∏ti)=c4(1−1)=−c4
∴∏xi=∏yi
Hence, option 'D' is correct.