The value of ${sin}^{2} 20^{o} + {sin}^{2} 70^{o} - {tan}^{2} 45^{o}$ is :

0

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Solution

The correct option is A $0$
${sin}^{2} 20^{o} + {sin}^{2} 70^{o} - {tan}^{2} 45^{o} \Rightarrow {sin}^{2} (90^{o} - 70^{o}) + {sin}^{2} 70^{o} - 1 \Rightarrow {cos}^{2} 70^{o} + {sin}^{2} 70^{o} - 1 = 1 - 1 = 0$

Therefore, Answer is $0$

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